Physics - SHM Question with Solution | TestHub

The K.E. of pendulum $\begin{array}{rl}& =\mathrm{K}.\mathrm{E}.\\ & =\frac{1}{2}K\left(a^2-y^2\right)\end{array}$ and P.E. of pendulum $=\frac{1}{2}K{Y}^2$ when $y=0$ (mean position) K.E. is maximum and PE is 0 . When $y=0$, K.E. is 0 and P.E. is maximum. $\therefore$ The displacement between position of maximum potential energy and maximum kinetic energy is $\pm a$.