For the given combination of gates, if the logic states of inputs $A, B, C$ are as follows $A = B = C = 0$ and $A = B = 1, C = 0$ then the logic states of output D are

Question

For the given combination of gates, if the logic states of inputs A , B , C are as follows A = B = C = 0 and A = B = 1 , C = 0 then the logic states of output D are

TestHub · Accepted Answer

To determine the output D, we analyze the circuit for the given input conditions.

Case 1: $A = B = C = 0$

Output of NOR gate 1 ( $X$ ) = $\overline{A + B} = \overline{0 + 0} = \overline{0} = 1$

Output of NAND gate ( $D$ ) = $\overline{X \cdot Y} = \overline{1 \cdot 0} = \overline{0} = 1$

Case 2: $A = B = 1, C = 0$

Output of NOR gate 1 ( $X$ ) = $\overline{A + B} = \overline{1 + 1} = \overline{1} = 0$

Output of NAND gate ( $D$ ) = $\overline{X \cdot Y} = \overline{0 \cdot 0} = \overline{0} = 1$

Thus, the logic states of output D are 1 and $1$ respectively.

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