Physics - Semiconductors Question with Solution | TestHub

From the given logic circuit diagram, we can determine the Boolean expressions for the outputs $Y_1$, $Y_2$, and $Y_3$.

The output $Y_1$ is the result of a NOR gate with inputs $A$ and $B$, followed by a NOT gate:
$Y_1=\overline{\overline{A+B}}=A+B$

The output $Y_2$ is the result of an AND gate with inputs $C$ and $D$:
$Y_2=C\cdot D$

The output $Y_3$ is the result of a NOR gate with inputs $Y_1$ and $Y_2$:
$Y_3=\overline{Y_1+Y_2}$

Given the new input conditions: $A=0$, $B=1$, $C=0$, and $D=1$.

Substituting these values into the expressions:
$Y_1=0+1=1$
$Y_2=0\cdot 1=0$
$Y_3=\overline{1+0}=\overline{1}=0$

Therefore, the outputs $Y_1$, $Y_2$, and $Y_3$ are $1,0,0$ respectively.

Answer: $1,0,0$