Physics - Semiconductors Question with Solution | TestHub

In a p-n junction, the depletion region contains immobile positive donor ions on the n-side and negative acceptor ions on the p-side.

According to Gauss's law, $\frac{dE}{dx}=\frac{\rho }{\epsilon }$. The electric field is directed from the n-side to the p-side.

The magnitude of the electric field increases as we move from the edges of the depletion region towards the junction, reaching its maximum value exactly at the metallurgical junction (the middle of the depletion region).

Therefore, the electric field is maximum in the middle of the depletion region.

Answer: electric field is maximum