A combination of logic gates is as shown in the figure. P, Q, R and S are the inputs and X, Y and Z are outputs. When inputs P and R are "low" and Q and S are "high", the outputs X, Y and Z respectively are

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From the given logic circuit, the Boolean expressions for the outputs are:
$X = P \cdot \overset{ˉ}{Q}$
$Y = \overline{R \cdot S}$
$Z = X + Y$

Given the inputs: $P = 0$ (low), $Q = 1$ (high), $R = 0$ (low), and $S = 1$ (high).

Substituting these values:
$X = 0 \cdot \overset{ˉ}{1} = 0 \cdot 0 = 0$
$Y = \overline{0 \cdot 1} = \overset{ˉ}{0} = 1$
$Z = 0 + 1 = 1$

Thus, the outputs $X, Y$ , and $Z$ are $0, 1$ , and $1$ respectively.

Answer: $0, 1, 1$

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