Physics - Semiconductors Question with Solution | TestHub

Let the three inputs from top to bottom be $A$, $B$, and $C$.

The first logic gate is an AND gate. Its output is $A\cdot B$.

The second logic gate is a NAND gate. Its inputs are $(A\cdot B)$ and $C$.

The final output $Y$ is given by the Boolean expression:
$Y=\overline{(A\cdot B)\cdot C}=\overline{A\cdot B\cdot C}$

Case 1: When all three inputs are high ($A=1,B=1,C=1$)
$Y=\overline{1\cdot 1\cdot 1}=\overline{1}=0$

Case 2: When all three inputs are low ($A=0,B=0,C=0$)
$Y=\overline{0\cdot 0\cdot 0}=\overline{0}=1$

Therefore, the outputs are $0$ and $1$ respectively.

Answer: $0,1$