Physics - Semiconductors Question with Solution | TestHub

The inputs $A$ and $B$ are passed through NOT gates, giving outputs $\bar{A}$ and $\bar{B}$.

These outputs are fed into a NOR gate. The Boolean expression for the final output $Y$ is:

$Y=\overline{\bar{A}+\bar{B}}$

Using De Morgan's theorem, $\overline{X+Y}=\bar{X}\cdot \bar{Y}$:

$Y=\overline{\bar{A}}\cdot \overline{\bar{B}}$

$Y=A\cdot B$

This represents the Boolean expression for an AND gate.

Answer: AND Gate