Physics - Semiconductors Question with Solution | TestHub

Let the inputs be $A$ and $B$, and the output be $Y$.

Given conditions:
When $A=0$ and $B=0$, $Y=1$.
When $A=1$ and $B=0$, $Y=0$.

Checking the given options:
For a NAND gate: $Y=\overline{A\cdot B}$. If $A=1,B=0$, $Y=\overline{0}=1$. This does not match.
For an OR gate: $Y=A+B$. If $A=0,B=0$, $Y=0$. This does not match.
For a NOR gate: $Y=\overline{A+B}$. If $A=0,B=0$, $Y=\overline{0}=1$. If $A=1,B=0$, $Y=\overline{1}=0$. This matches both conditions.
For an XOR gate: $Y=A\oplus B$. If $A=0,B=0$, $Y=0$. This does not match.

Therefore, the logic gate is a NOR gate.

Answer: NOR