Physics - Semiconductors Question with Solution | TestHub

From the given logic circuit, the output of the OR gate is $A+B$.

This output is fed into an AND gate along with input $C$.

Therefore, the final output $Y$ is given by the Boolean expression:

$Y=(A+B)\cdot C$

We need the output $Y$ to be $0$. Let us evaluate the given choices:

For choice a: $A=1,B=1,C=0\Rightarrow Y=(1+1)\cdot 0=1\cdot 0=0$

For choice b: $A=0,B=1,C=0\Rightarrow Y=(0+1)\cdot 0=1\cdot 0=0$

For choice c: $A=1,B=1,C=1\Rightarrow Y=(1+1)\cdot 1=1\cdot 1=1$

For choice d: $A=1,B=0,C=1\Rightarrow Y=(1+0)\cdot 1=1\cdot 1=1$

Thus, choices a and b give an output of zero.

Answer: a and b