Physics - Semiconductors Question with Solution | TestHub

The given logic circuit consists of three gates.

The upper gate is a NAND gate with inputs $A$ and $B$. Its output is $\overline{A\cdot B}$.

The lower gate is a NOR gate with inputs $B$ and $C$. Its output is $\overline{B+C}$.

The final gate is an OR gate which takes the outputs of the NAND and NOR gates as its inputs.

Therefore, the final output $Y$ is given by the logical OR operation of these two intermediate outputs:

$Y=\overline{A\cdot B}+\overline{B+C}$

Answer: $\overline{(A\cdot B)}+\overline{(B+C)}$