Physics - Semiconductors Question with Solution | TestHub

From the given logic circuit, the inputs $A$ and $B$ are first passed through NOT gates.

The outputs of the NOT gates are $\overline{A}$ and $\overline{B}$.

These outputs are then fed as inputs to a NAND gate. The Boolean expression for the final output $Y$ is:
$Y=\overline{\overline{A}\cdot \overline{B}}$

Using De Morgan's theorem ($\overline{X\cdot Y}=\overline{X}+\overline{Y}$), we can simplify the expression:
$Y=\overline{\overline{A}}+\overline{\overline{B}}$

Since the double inversion of a variable is the variable itself ($\overline{\overline{A}}=A$), we get:
$Y=A+B$

The Boolean expression $Y=A+B$ represents an OR gate.

Answer: OR