Physics - Semiconductors Question with Solution | TestHub

Given:
Current gain, $\beta =8$
Input impedance, $R_{in}=25\text{ k}\Omega$
Load resistance, $R_L=75\text{ k}\Omega$

The power gain $A_p$ of a transistor in common emitter mode is given by the formula:
$A_p={\beta }^2\times \frac{R_L}{R_{in}}$

Substituting the given values:
$A_p=(8{)}^2\times \frac{75}{25}$

$A_p=64\times 3=192$

Answer: $192$