Physics - Semiconductors Question with Solution | TestHub

The logic circuit consists of a NOR gate and an AND gate.

The inputs to the NOR gate are $A$ and $B$, so its output is $\overline{A+B}$.

This output and input $C$ are fed into the AND gate. The final output $Y$ is given by the Boolean expression:

$Y=(\overline{A+B})\cdot C$

The question asks for the input combination that should NOT be used to get an output of $0$. This means we need to find the inputs that result in an output of $1$.

For $Y=1$, both inputs to the AND gate must be $1$.

Therefore, $\overline{A+B}=1$ and $C=1$.

For the NOR gate output to be $1$, both inputs $A$ and $B$ must be $0$.

Thus, $A=0$ and $B=0$.

The required inputs are $A=0,B=0,C=1$.

Answer: 0,0,1