Physics - Semiconductors Question with Solution | TestHub

Let us analyze the logic circuit step-by-step:

The inputs to the top AND gate are $A$ and $B$. Its output is $A\cdot B$.

This output passes through a NOT gate, giving $\overline{A\cdot B}$.

The inputs to the bottom AND gate are $\overline{A}$ (since input $A$ passes through a NOT gate) and $B$. Its output is $\overline{A}\cdot B$.

These two outputs are fed into an OR gate.

Therefore, the final output $Y$ is the logical OR of these two signals, which is given by:
$Y=(\overline{A\cdot B})+(\overline{A}\cdot B)$

Answer: $(\overline{\mathrm{A}\cdot \mathrm{B}})+(\overline{\mathrm{A}}\cdot \mathrm{B})$