Physics - Semiconductors Question with Solution | TestHub

From the given circuit diagram, the potential at the P-side of the diode is $V_P=-5\text{ V}$.

The N-side of the diode is connected to a potential of $-2\text{ V}$ through a $500\Omega$ resistor.

For a diode to be forward-biased and conduct current, the potential at the P-side must be greater than the potential at the N-side ($V_P>V_N$).

Here, $V_P=-5\text{ V}$ and the potential applied to the N-side is $-2\text{ V}$. Since $-5\text{ V}<-2\text{ V}$, the P-side is at a lower potential than the N-side.

Therefore, the diode is reverse-biased.

An ideal reverse-biased diode acts as an open circuit, offering infinite resistance.

Hence, the current flowing through the circuit is zero.

Answer: zero