Physics - Semiconductors Question with Solution | TestHub

For combination (I):

The first two NAND gates have their inputs tied together, so they act as NOT gates.

The input to both the top and bottom NAND gates is $0$. Their outputs will be $\overline{0\cdot 0}=1$.

These outputs ($1$ and $1$) are fed as inputs to the third NAND gate.

The final output of combination (I) is $\overline{1\cdot 1}=0$.

For combination (II):

The first NAND gate has inputs $1$ and $1$. Its output is $\overline{1\cdot 1}=0$.

This output is fed into the second NAND gate, which has its inputs tied together (acting as a NOT gate).

The final output of combination (II) is $\overline{0\cdot 0}=1$.

Therefore, the outputs of the combinations are $0$ and $1$ respectively.

Answer: 0,1