In the study of transistor as an amplifier if α = I E I C = 0.98 and β = I B I C = 49 , where I C , I B and I E are cóllector, base and emitter current respectively then ( α 1 − β

Question

In the study of transistor as an amplifier if $α = \frac{I _{C}}{I _{E}} = 0.98$ and $β = \frac{I _{C}}{I _{B}} = 49$ , where $I_{C}, I_{B}$ and $I_{E}$ are cóllector, base and emitter current respectively then $(\frac{1}{α} - \frac{1}{β})$ is equal to

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Answer:

D

Solution:

$\frac{1}{α} - \frac{1}{β} = \frac{1}{0.98} - \frac{1}{4.9} = 1.204 - 0.204 = 1$

TestHub · Accepted Answer

α 1 ​ − β 1 ​ ​ = 0.98 1 ​ − 4.9 1 ​ = 1.204 − 0.204 = 1 ​

Physics - Semiconductors Question with Solution | TestHub

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