Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionEasy2 minPYQ_2022

PhysicsEasyinteger

The cut-off voltage of the diodes (shown in figure) in forward bias is $0.6 V$ . The current through the resister of $40 Ω$ is _____ $mA$ .

Answer:

Solution:

Here diode $D_{1}$ is forward biased and diode $D_{2}$ is reverse biased.

So, no current will flow through diode $D_{2}$ resistor.

Current through the resistor of $40 Ω$ is $i = \frac{1 - 0.6}{60 + 40} = \frac{0.4}{100} = 4 mA$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2022

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