Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionEasy2 minPYQ_2022

PhysicsEasyinteger

If the potential barrier across a $p - n$ junction is $0.6 V$ . Then the electric field intensity, in the depletion region having the width of $6 \times 10^{- 6} m$ , will be _____ $\times 10^{5} N C^{- 1}$

Answer:

Solution:

Electric field intensity is $E = \frac{V}{d} = \frac{Potential barrier across junction}{width of depletion region}$
$= \frac{0.6 V}{6 \times 10^{- 6} m} = 1 \times 10^{5} V m^{- 1}$
$= 1 \times 10^{5} N C^{- 1}$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2022

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