Physics - Semiconductors Question with Solution | TestHub

The diode is forward biased. The potential difference between $\mathrm{P}$ and $\mathrm{Q}$ is $(3-(-5))=8\mathrm{V}$. $$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{8}{2\times 10^3}=4\times 10^{-3}\mathrm{A}$$