Physics - Semiconductors Question with Solution | TestHub

Truth table: \begin{array}{|l|l|l|l|l|} \hline A & B & C & D & Y \\ \hline 0 & 0 & 1 & 1 & 0 \\ \hline 0 & 1 & 1 & 0 & 0 \\ \hline 1 & 0 & 0 & 1 & 0 \\ \hline 1 & 1 & 0 & 0 & 1 \\ \hline \end{array} This is truth table of AND gate. $\therefore \mathrm{Y}=\mathrm{A}\cdot \mathrm{B}$