For a transistor, α D C 1 − β D C 1 is equal to [ α D C and β D C are current amplification factors]

α D C 1 − β D C 1 = I c I e − I c I b I c I e − I b = I c I c = 1

Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsTransistorHard2 minPYQ_2021

PhysicsHardsingle choice

For a transistor, $\frac{1}{α _{D C}} - \frac{1}{β _{D C}}$ is equal to $[α_{D C}$ and $β_{D C}$ are current amplification factors]

Answer:

Solution:

$\frac{1}{α _{D C}} - \frac{1}{β _{D C}} = \frac{I _{e}}{I _{c}} - \frac{I _{b}}{I _{c}} \frac{I _{e} - I _{b}}{I _{c}} = \frac{I _{c}}{I _{c}} = 1$

Stream:MHT_CETSubject:PhysicsTopic:SemiconductorsSubtopic:Transistor

⏱ 2mℹ️ Source: PYQ_2021

Loading discussions...