Physics - Semiconductors Question with Solution | TestHub

Output of the above circuit can be obtained as

$y=\left(\overline{A\cdot B}\right)\cdot (A+B)$

$y=(\overline{A}+\overline{B})\cdot (A+B)$

$y=\overline{A}.B+\overline{B}.A+A.\overline{A}+B.\overline{B}$

$y=\overline{A}.B+\overline{B}.A+0+0$

$y=\overline{A}.B+\overline{B}.A$, which is XOR gate