Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPhysics of semiconductorEasy2 minPYQ_2020

PhysicsEasysingle choice

The electrical conductivity of a semiconductor increases when electromagnetic radiation of a wavelength shorter than $2480 nm$ is incident on it. The bandgap in $(eV)$ for the semiconductor is [take $hc = 12400 eV \overset{\circ}{A}$ ]

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Answer:

Solution:

$λ_{max} = 2480 nm = 24800 Å$

Energy (in $eV$ ) $= \frac{12400 e V Å}{λ}$

$E = \frac{12400}{24800} eV$

$E= 0.5 eV$

Subject:PhysicsTopic:SemiconductorsSubtopic:Physics of semiconductor

⏱ 2mℹ️ Source: PYQ_2020

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