A common emitter transistor amplifier is connected with a load resistance of 6 k Ω . When a small a.c. signal of 15 mV is added to the base emitter voltage, the alternating base current is 20 μ A and

Question

A common emitter transistor amplifier is connected with a load resistance of 6 k Ω . When a small a.c. signal of 15 mV is added to the base emitter voltage, the alternating base current is 20 μ A and the alternating collector current is 1.8 mA . What is the voltage gain of the amplifier?

TestHub · Accepted Answer

Hint: R C ​ = 6 × 1 0 3 Ω Δ l B ​ R B ​ = 15 × 1 0 − 3 V Δ I B ​ = 20 × 1 0 − 6 A Δ l C ​ = 1.8 × 1 0 − 3 A A v ​ = β × R B ​ R C ​ ​ = Δ B ​ Δ l C ​ ​ × R B ​ R C ​ ​ = 20 × 1 0 − 6 1.8 × 1 0 − 3 ​ × 15 × 1 0 − 3 6 × 1 0 3 × 20 × 1 0 − 6 ​ = 720

Physics - Semiconductors Question with Solution | TestHub

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