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PhysicsSemiconductorsPN junctionEasy2 minPYQ_2020

PhysicsEasysingle choice

A $p - n$ junction has acceptor impurity concentration of $10^{17} {c m}^{- 3}$ in the $p$ side and donor impurity concentration of $10^{16}$ ${c m}^{- 3}$ in the $n$ side. The contact potential at the junction is ( $k T =$ thermal energy, intrinsic carrier concentration $n_{i} = 1.4 \times 10^{10}$ ${c m}^{- 3}$ )

Options:

Answer:

Solution:

Constant potential at the junction

$V_{c o n s t a n t} = \frac{k T}{e}$ ln $(\frac{n_{a} n_{d}}{n_{i}^{2}})$

$V_{c o n s t a n t} = \frac{k T}{e}$ ln $(\frac{10^{17} \times 10^{16}}{{(1.4 \times 10^{10})}^{2}}) = \frac{k T}{e}$ ln ( ${4 \times 10}^{12}$ )

Subject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2020

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