Physics - Semiconductors Question with Solution | TestHub

Output of upper OR gate$=P+R$

Output of lower OR gate$=P+Q$

$\therefore$Net output$A=\left(P+R\right).\left(P+Q\right)$

$=P.P+P.Q+R.P+R.Q$

$=P.\left(1+Q\right)+R.P+R.Q$

$\because$$1+Q=1 and P.P=P$

$\therefore$$A=P+R\cdot P+R.Q$

$=P\left(1+R\right)+R\cdot Q=P+R\cdot Q$