Physics - Semiconductors Question with Solution | TestHub

Here,$I=\frac{70}{5000}=\text{1.4}\times 10^{-2} A$

$V_{\text{Z}}=120-70$

$=50 V$(output voltage Across diode)

$I_{\mathrm{L}}=\frac{50}{10000}=5\times 10^{-3} A=\text{0.5}\times 10^{-2} A$

$\Rightarrow I_{\text{Z}}=\left(\text{1.4}-\text{0.5}\right)\times 10^{-2} A$

$=9\times 10^{-3} A$

$= 9 \mathrm{mA}$