Physics - Semiconductors Question with Solution | TestHub

Given that, change in emitter current,${∆I}_E=$8 mA

and change in collector current,${∆I}_C=7.9$mA

We know that,

$\mathrm{\alpha }=\frac{{∆I}_C}{{∆I}_E}$

$\Rightarrow =\frac{7.9}{8}\Rightarrow$$\mathrm{\alpha }\approx$0.99

Also, we know that

$\mathrm{\beta }=\frac{\alpha }{1-\alpha }$

$\Rightarrow =\frac{\frac{7.9}{8}}{1-\frac{7.9}{8}}=\frac{7.9}{8-7.9}$

Or$\mathrm{\beta }=\frac{7.9}{0.1}$= 79

Hence, the required answer is$\mathrm{\alpha }=$0.99 and$\mathrm{\beta }=79.$