For common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 4 V. If the current amplification factor of the transistor is 100 and the base resistance

Question

For common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 k Ω then the input signal voltage is

TestHub · Accepted Answer

R C = 2 k Ω V 0 = 4 V I C = V 0 R c = 4 V 2 k Ω = 2 m A β = I C I B = 100 ⇒ I B = I C 100 = 2 × 10 - 5 A V i n = I B R i = 2 × 10 - 5 × 1 k Ω = 20 m V

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