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Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsLogic gatesMedium2 minPYQ_2019

PhysicsMediumsingle choice

To get output'1' at $R,$ for the given logic gate circuit the input values must be:

Options:

Answer:

Solution:

$R = \bar{(\bar{X} + Y) + (\bar{X \cdot \bar{Y}})} = (\bar{\bar{X} + Y}) \cdot (\bar{\bar{X . \bar{Y}}}) = (X . \bar{Y}) \cdot (X . \bar{Y}) = (X . \bar{Y})$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:Logic gates

⏱ 2mℹ️ Source: PYQ_2019

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