Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsPN junctionMedium2 minPYQ_2018

PhysicsMediumsingle choice

If current in diode is five times that in $R_{1}$ . Breadkdown voltage of diode is 6 volt. Find the value of $R$ .

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Answer:

Solution:

Current in diode is 5 times that in $R_{1}$ . Current through $R_{1}$ is $I_{1} = \frac{V}{R _{1}} = \frac{6}{1 \times 1 0 ^{3}} A = 6 mA$ So total current drawn from battery $= 6 mA + 30 mA = 36 mA$ Potential difference across $R = 24$ volt So $V = I R; 24 = 36 \times 1 0^{- 3} R; R = 2000/3Ω$

Stream:AIIMSSubject:PhysicsTopic:SemiconductorsSubtopic:PN junction

⏱ 2mℹ️ Source: PYQ_2018

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