Physics - Semiconductors Question with Solution | TestHub

Breakdown voltage of Zener diode $=5.6\mathrm{V}$ Voltage of source $=10\mathrm{V}$ Potential difference $\Delta V=(10-5.6)\mathrm{V}=4.4\mathrm{V}$ Resistance of circuit $=100\Omega$ The current passing through the Zener diode $$\begin{array}{rl}l& =\frac{\Delta V}{R}\\ & =\frac{4.4}{100}\\ & =4.4\times 10^{-2}\mathrm{A}\\ & =44\times 10^{-3}\mathrm{A}\\ & =44\mathrm{mA}\end{array}$$