Physics - Semiconductors Question with Solution | TestHub

PhysicsSemiconductorsLogic gatesEasy2 minPYQ_2014

PhysicsEasysingle choice

Identify the gate and match $A, B, Y$ in the bracket to check.

Answer:

Solution:

The output of the first NAND gate

$Y^{'} = \bar{A \cdot B}$

The output of the second NAND gate

$Y = \bar{(\bar{A \cdot B}) \cdot (\bar{A \cdot B})} \Rightarrow Y = (\bar{\bar{A \cdot B}}) + (\bar{\bar{A \cdot B}}) \Rightarrow Y = A \cdot B$

So, the equivalent circuit will be an AND gate.

$A N D (A = 1, B = 1, Y = 1)$

Stream:JEESubject:PhysicsTopic:SemiconductorsSubtopic:Logic gates

⏱ 2mℹ️ Source: PYQ_2014

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