In a common emitter configuration, a transistor has β = 50 and input resistance 1 k Ω . If the peak value of a.c. input is 0.01 V then the peak value of collector current is

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Hints: β = 50 ⇒ β = Δ I B ​ Δ I C ​ ​ ⇒ Δ I C ​ = β × Δ I B ​ ​ Δ I B ​ = 1 0 3 0.01 ​ = 1 0 − 2 × 1 0 − 3 = 1 0 − 5 Δ I C ​ = 50 × 1 0 − 5 = 500 × 1 0 − 6 = 500 μ A ​

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