Physics - Semiconductors Question with Solution | TestHub

Given that, change in emitter current, $\Delta I_E=8\mathrm{mA}$ and change in collector current, $\Delta I_C=7.9\mathrm{mA}$ We know that, $$\alpha =\frac{\Delta I_C}{\Delta I_E}\Rightarrow \alpha =\frac{7.9}{8}\Rightarrow \alpha \simeq 0.99$$ Also we know that $$\begin{array}{c}\beta =\frac{\alpha }{1-\alpha }\\ \Rightarrow \beta =\frac{\frac{7.9}{8}}{1-\frac{7.9}{8}}=\frac{7.9}{8-7.9}\end{array}$$ or $\beta =\frac{7.9}{0.1}=79$ Hence, the required answer is $\alpha =0.99$ and $\beta =79$