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Physics - Rotation Question with Solution | TestHub

PhysicsRotationEnergy in rotationEasy2 minQB

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An automobile moves on a road with a speed of $54 k m h^{- 1}$ . The radius of its wheels is $0.45 m$ and the moment of inertia of the wheel about its axis of rotation is $3 k g m^{2}$ . If the vehicle is brought to rest in $15 s$ , the magnitude of average torque transmitted by its brakes to the wheel is:

Options:

Answer:

Solution:

$ω_{i} = \frac{15}{0.45} = \frac{100}{3} ω_{f} = 0$

$ω_{f} = ω_{i} + α t$

$0 = \frac{100}{3} + (- α) (15)$

$α = \frac{100}{45}$

$τ = (I) (α) = 3 \times \frac{100}{45} = 6.66 N . M$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Energy in rotation

⏱ 2mℹ️ Source: QB

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