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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCollision in RotationEasy2 minQB

PhysicsEasysingle choice

A uniform rod of mass $M_{1}$ is hinged at its upper end. A particle of mass $M_{2}$ moving horizontally strikes the rod at its midpoint elastically. If the particle comes to rest after collision, then, Find the value of $\frac{M_{1}}{M_{2}}$

Options:

Answer:

Solution:

Angular Momentum about Hinge

$L_{H} = I_{H} . ω$

$(I_{H} = \frac{m_{1} l^{2}}{3})$

$L_{H} = M_{2} v \frac{L}{2} = \frac{M_{1} L^{2}}{3} ω$

$ω = \frac{3 M_{2} v}{2 M_{1} L} \dots (1)$

for $e = 1, v_{C M} = v = \frac{ω L}{2} \dots (2)$

$\Rightarrow \frac{2 v}{L} = \frac{3 M_{2} v}{2 M_{1} L}$

$\Rightarrow \frac{M_{1}}{M_{2}} = \frac{3}{4}$

$= 0.75$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Collision in Rotation

⏱ 2mℹ️ Source: QB

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