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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCollision in RotationEasy2 minQB

PhysicsEasynumerical

A uniform rod of mass $M_{1}$ is hinged at its upper end as shown in the figure. A particle of mass $M_{2}$ which is moving horizontally, strikes the rod elastically at its midpoint. If the particle comes to rest after collision, then the value of $\frac{M_{1}}{M_{2}}$ is

Answer:

0.75

Solution:

Conserving angular Momentum about the hinge, just before and after the collision

$L_{H} = M_{2} v \frac{L}{2} = \frac{M_{1} L^{2}}{3} ω$

$ω = \frac{3 M_{2} v}{2 M_{1} L}$

$e = 1, v_{C M} = v = \frac{ω L}{2}$

$\Rightarrow \frac{2 v}{L} = \frac{3 M_{2} v}{2 M_{1} L}$

$\Rightarrow \frac{M_{1}}{M_{2}} = \frac{3}{4}$

$= 0.75$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Collision in Rotation

⏱ 2mℹ️ Source: QB

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