Physics - Rotation Question with Solution | TestHub

PhysicsRotationMiscellaneousMedium3 minQB

PhysicsMediuminteger

The figure shown is in equilibrium. Find out the extension in the spring (in cm).

CT42 n1 diagram

Answer:

500

Solution:

For the 40 kg mass, the right string tension is $400 N$ .

Taking moments about the fixed axle: $T_{L} (0.2) = 400 (0.6)$ , so $T_{L} = 1200 N$ .

For the 70 kg mass, equilibrium gives $T_{L} = 700 + k x$ , hence $k x = 500 N$ .

With $k = 100 N / m$ , $x = 5 m = 500 c m$ .

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Miscellaneous

⏱ 3mℹ️ Source: QB

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