Physics - Rotation Question with Solution | TestHub

PhysicsRotationCollision in RotationHard2 minQB

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Passage / Comprehension

A uniform wire frame of linear mass density $λ$ having three sides each of length 2 a is kept on a smooth horizontal surface. An impulse J is applied at one end as shown in the figure. P is the midpoint of AB.\\

The velocity of point P just after the impulse is

Options:

Answer:

Solution:

$J \times a = {[\frac{M ( 2 a ) ^{2}}{12} + M (\frac{2 a}{3})^{2}] + 2 [\frac{M ( 2 a ) ^{2}}{12} + M (\frac{10 a ^{2}}{9})]} ω ω = \frac{3 J}{22 λ a ^{2}} V = V_{c m} \hat{j} + ω (\frac{2 a}{3}) \hat{i} = \frac{J}{3 m} \hat{j} + \frac{2 a}{3} \cdot \frac{3 J}{22 λ a ^{2}} \hat{i} = \frac{J}{6 λa} \hat{j} + \frac{J}{11 λa} \hat{i}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Collision in Rotation

⏱ 2mℹ️ Source: QB

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