A uniform ring is rotating about the vertical axis with angular velocity $ω$ initially. A point insect ( $S$ ) having the same mass as that of the ring starts walking from the lowest point $P_{1}$ and finally reaches the point $P_{2}$ (as shown in the figure). The final angular velocity of the ring is

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From the conservation of angular momentum 1 2 M R 2 ω = 1 2 MR 2 + MR 2 ω ´ ⇒ 1 2 MR 2 ω = 3 2 MR 2 ω ´ ⇒ ω ´ = ω 3

Physics - Rotation Question with Solution | TestHub

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