Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationEasy2 minQB
PhysicsEasynumerical

A uniform rodABof mass2 kgand length1 mis placed on a sharp supportO, such thatAO=a=25 cmandOB=b=75 cm. A spring of force constant600 N m-1is attached to the endB, as shown. Initially, the spring is extended by2 cmat equilibrium. As soon as the thread is burnt, find the normal force (inN) exerted by the support atO.


Answer:
8.00
Solution:

IaboutOismL212+mL216=7mL248

Spring force⇒KΔx=600×2100=12  N

Torque, just after burning the string,

τ=2×10×14+12×34

⇒ τ= 5 + 9 = 14 N m

∴α=14×487×2×1=48 rad s-2

∴Acceleration of COM,

a=48×14=12 m s-2

Now, total vertical force

12 + 20 – N = 2 × 12

⇒N = 32 – 24 = 8 N

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration
⏱ 2mℹ️ Source: QB

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