Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium2 minQB

PhysicsMediummultiple choice

A man of mass $m$ on an initially stationary boat gets off the boat by leaping to the left in an exactly in horizontal direction. Immediately after the leap, the boat of mass M , is observed to be moving to the right at speed v

Options:(select one or more)

Answer:

B, D

Solution:

From momentum conservation $m v_{man} = M v$

For [a]: Work done by man on boat $= Δ K E_{boat} = \frac{1}{2} M v^{2}$

For [b]: $W_{man total} = Δ K E_{system} = \frac{1}{2} m \frac{M ^{2} v ^{2}}{m ^{2}} + \frac{1}{2} M v^{2}$

For [c]: $v_{CM} = 0$ {momentum conservation\}

For [d]: $W_{man on himdelf} = Δ K E_{man} = \frac{1}{2} \frac{M ^{2}}{m} v^{2}$

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

⏱ 2mℹ️ Source: QB

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