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Physics - Rotation Question with Solution | TestHub

PhysicsRotation283Medium2 minQB

PhysicsMediumsingle choice

A light rod carries three equal masses A, B and C as shown in figure. The velocity of B in vertical position of rod if it is released from horizontal position as shown in figure is :-

Options:

Answer:

Solution:

Energy: $\frac{1}{2} I ω^{2} = m g (\frac{ℓ}{3} + \frac{2 ℓ}{3} + ℓ)$ with $I = \frac{14}{9} m ℓ^{2}$

$ω^{2} = \frac{18 g}{7 ℓ}$ , so $v_{B} = ω \times \frac{2 ℓ}{3} = \frac{8 g ℓ}{7}$

Answer (D)

Stream:JEESubject:PhysicsTopic:RotationSubtopic:283

⏱ 2mℹ️ Source: QB

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