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PhysicsRotationCalculation of M.I.Medium2 minQB

PhysicsMediuminteger

A uniform semicircular disc of mass ' M ' and radius ' R ' hinged at point O as shown in figure is released from rest from a vertical position as shown. If the initial magnitude of angular acceleration of the disc is $\frac{xg}{3 π R}$ than the value of $x$ is (Center of mass is at a distance $\frac{4 R}{3 π}$ from center of disc):

Answer:

Solution:

$τ = I α; τ = mg (\frac{4 R}{3 π}); I = \frac{MR ^{2}}{2}, α = \frac{8 g}{3 π R} \Rightarrow x = 8$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: QB

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