Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Easy2 minPYQ_2025

PhysicsEasysingle choice

The moment of inertia of a circular ring of mass $M$ and diameter r about a tangential axis lying in the plane of the ring is :

Answer:

Solution:

Diameter is given as R.
$∴ Radius = R /2 I_{tan gent} = \frac{3}{2} m (\frac{R}{2})^{2} = \frac{3}{8} mR^{2}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2025

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