Physics - Rotation Question with Solution | TestHub

PhysicsRotationTorque / angular accelerationEasy2 minPYQ_2025

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A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg , kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is

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Answer:

Solution:

Torque about bottom point
$F \times 2 r = I α 49 \times 2 r = \frac{7}{5} mr^{2} α 14 = 4 r α$
As sphere rolls without slipping
$a = r α a = \frac{14}{4} = \frac{7}{2} = 3.5 m / s^{2}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Torque / angular acceleration

⏱ 2mℹ️ Source: PYQ_2025

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