Physics - Rotation Question with Solution | TestHub

PhysicsRotationTranslational + RotationalMedium2 minPYQ_2025

PhysicsMediumnumerical

A circular ring and a solid sphere having same radius roll down on an inclined plane from rest without slipping. The ratio of their velocities when reached at the bottom of the plane is $\frac{x}{5}$ where $x =$ _____

Answer:

4.00

Solution:

Applying Mechanical Energy conservation :
$k_{i} + U_{i} = k_{f} + U_{f}$
$\Rightarrow 0 + Mgh = \frac{1}{2} mv^{2} (1 + \frac{k ^{2}}{R ^{2}}) + 0 \Rightarrow V = \frac{2 gh}{1 + \frac{k ^{2}}{R ^{2}}}$
So Ratio of velocities
$\frac{V _{Ring}}{V _{solids sphere}} = \frac{1 + \frac{2}{5}}{1 + 1} = \frac{7}{10}$
$x = 3.5$ Rounding off $x = 4$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Translational + Rotational

⏱ 2mℹ️ Source: PYQ_2025

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