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Physics - Rotation Question with Solution | TestHub

PhysicsRotationCalculation of M.I.Hard2 minPYQ_2025

PhysicsHardsingle choice

A rod of linear mass density ' $λ$ ' and length ' $L$ ' is bent to form a ring of radius 'R'. Moment of inertia of ring about any of its diameter is :

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Answer:

Solution:

$L = 2 π R$
$I = \frac{MR ^{2}}{2} = \frac{λ \times L}{2} \times (\frac{L}{2 π})^{2} = \frac{λ L ^{3}}{8 π ^{2}}$

Stream:JEESubject:PhysicsTopic:RotationSubtopic:Calculation of M.I.

⏱ 2mℹ️ Source: PYQ_2025

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